Question 143103
(7x-9)/(x^2-25)-3/(x-5)=2/(x-5)
(7x-9)/x^2-25)=3/(x-5)+2/(x-5)
(7x-9)/(x-5)(x+5)=5/(x-5) now cancel out the (x-5) terms in the denominators.
(7x-9)/(x+5)=5 now cross multiply.
7x-9=5(x+5)
7x-9=5x+25
7x-5x=25+9
2x=34
x=34/2
x=17 answer.
Proof:
(7*17-9)/(17^2-25)-3/(17-5)=2/(17-5)
(119-9)/(289-25)-3/(17-5)=2/917-5)
110/264-3/12=2/12
5/12-3/12=2/12
2/12=2/12