Question 143133
AT LEAST YOU TRIED!!!
ACTUALLY YOU CAN CHECK YOUR ANSWER, AS FOLLOWS:

TIME IT TOOK LOCAL=50/58= 0.862 HR
TIME IT TOOK EXPRESS=50/75=0.66667 HR
THERE SHOULD BE AN HOURS DIFFERENCE AND THERE'S NOT

LOOK AT THIS APPROACH:


Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r

Let r= rate of the local
then 2r=rate of the express
Time it tool local to make the trip=50/r
Time it tool express to make the trip=50/2r

Now we are told that the express arrives 1 hour ahead of the local, so:

50/r -1 =50/2r  multiply each term by 2r

50*2-2r=50 or

100-2r=50  subtract 100 from each side

100-100-2r=50-100  collect like terms

-2r=-50  divide each side by -2

r=25 mph------------------------------speed of local

2r=2*25=50 mph----------------------------speed of the express

CK 
time it took local=50/25=2hrs
Local arrived at 5 PM
time it took express =50/50=1hr

express arrives at 4 PM

Hope this helps----ptaylor