Question 143158
y^2-3y-10=0
{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
y=(3+-sqrt[-3^2-4*1*-10])/2*1
y=(3+-sqrt[9+40])/2
y=(3+-sqrt49)/2
y=3+-7)/2
y=(3+7)/2
y=10/2
y=5 answer.
y=(3-7)/2
y=-4/2
y=-2 answer.