Question 143075
Eliminating the parameter in the parametric equations x = 5-3t, y = 2+t yields the equation 
a. y = -x + (11/3)
b y = (-x/3) + (11/3)
c. y = (-x/3) + (1/3)
d. y = (-x/3) - (1/3)
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Solve each equation for "t":
t = (5-x)/3
t = y-2
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Equate the expressions:
y-2 = (5-x)/3
y = (-1/3)x + 5/3 + 2
y = (-1/3)x + (11/3)
Ans: b
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Cheers,
Stan H.