Question 142944
{{{f(x)=2x^2-3x+3}}} Start with the given function



{{{f(4)=2(4)^2-3(4)+3}}} Plug in {{{x=4}}}



{{{f(4)=2*16-3*4+3}}} Raise 4 to the 2nd power to get 16



{{{f(4)=32-3*4+3}}} Multiply 2 and 16 to get 32



{{{f(4)=32-12+3}}} Multiply 3 and 4 to get 12



{{{f(4)=20+3}}} Subtract 12 from 32 to get 20



{{{f(4)=23}}} Add 20 and 3 to get 23



So when {{{x=4}}}, then {{{2x^2-3x+3=23}}}