Question 142920
{{{y=x^2+3x-10}}} Start with the given equation



{{{0=x^2+3x-10}}} To find the x-intercept(s), let y be equal to zero. So plug in {{{y=0}}}



{{{0=(x+5)(x-2)}}} Factor the right side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x+5=0}}} or  {{{x-2=0}}} 


{{{x=-5}}} or  {{{x=2}}}    Now solve for x in each case



So the x-intercepts are:


 {{{x=-5}}} and  {{{x=2}}} 



Notice if we graph {{{y=x^2+3x-10}}}  we can see that the x-intercepts are {{{x=-5}}} and  {{{x=2}}} . So this visually verifies our answer.



{{{ graph(500,500,-10,10,-10,10,0, x^2+3x-10) }}}