Question 142718
{{{y^2+y/2=-3/2}}}

Clear of fractions by multiplying every term by 2

{{{2(y^2)+2(y/2)=2(-3/2)}}}

{{{2(y^2)+cross(2)(y/cross(2))=cross(2)(-3/cross(2))}}}

{{{2y^2+y=-3}}}

Now put it in its correct form.  It would have been OK
to put it in the corret form first.  Add 3 to both
sides:

{{{2y^2+y+3=0}}}

Use quadratic formula since it doesn't factor.

{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

{{{a=2}}}, {{{b=1}}}, {{{c=3}}}

{{{y = (-1 +- sqrt( 1^2-4*2*3 ))/(2*2) }}}

{{{y = (-1 +- sqrt( 1-24 ))/4 }}}

{{{y = (-1 +- sqrt( -23 ))/4 }}}
 
{{{y = (-1 +- i*sqrt( 23 ))/4 }}}

Edwin</pre>