<PRE><B>Question 142690</B>
Find the measue of angel C in the triangle with the following dimensions a= 28, b= 35, c= 17
a. 52.16
b. 42.39
c. 28.65
d. 31.72
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Law of Cosines:
Cos(C) = (a^2+b^2-c^2)/2ab
Cos(C) = (28^2+35^2+17^2)/(2*28*35) = 0.8775510...
C = cos^-1(0.8775510..) = 28.65
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Cheers,
Stan H. </PRE>