Question 2420
0=x^2-12x+16 
0=ax^2-bx+c
-b+- square root of (b^2-4ac) / 2(a)

12+- square root of <-12^2-4(1)(16)
12+- square root of (144-64)
12+- square root of (80)
12+- square root of (80) / 2