Question 142542
the operation is 6 divided by 3+i


the fraction is an answer, but complex numbers are a no-no in the denominator


multiplying by the conjugate (3-i) on the top and bottom is the way to go


[6(3-i)]/[(3+i)(3-i)] __ (18-6i)/(9-i^2) __ 18/10-6i/10 __ 9/5-3i/5