Question 142542
6/(3 + i)
Multiply numerator and denominator by 3-i to get:

= [6(3-i)]/[(3+i)(3-i)]

= [6(3-i)]/[9+1]

= [3(3-i)]/[5]

= (9/5) - (3/5)i
=====================
Cheers,
Stan H.