Question 142543
{{{7x^(5/3)=36}}} Start with the given equation



{{{cross(7)x^(5/3)/cross(7)=36/7}}} Divide both sides by 7



{{{x^(5/3)=5.14286}}} Divide



{{{(x^(5/cross(3)))^cross(3)=5.14286^3}}} Cube both sides. This will eliminate the denominator 3 in the exponent



{{{x^5=136.02355}}} Cube 5.14286 to get 46,656 



{{{root(cross(5),x^cross(5))=root(5,136.02355)}}} Take the 5th root of both sides. This will cancel out the exponent 5



{{{x=2.67130}}} Take the 5th root of  136.02355 to get approximately 2.67130




So our answer is {{{x=2.67130}}}