Question 142509
{{{f(x)=1/(x+2) }}} 


There is an asymptote at x=-2, since the denominator cannot = 0 at x=-2.  


Plot a few points:
If x=0, then f(0) =1/2.  
If x=1, then f(1) = 1/3
If x=-1, then f(-1)= 1
If x=-3, then f(-3)=-1


The graph should look like this:
{{{graph(300,300, -6,6,-6,6, 1/(x+2) )}}}


R^2