Question 142361


Let's denote the first point (-3,-6) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=-3] and *[Tex \LARGE y_{1}=-6]


Now let's denote the second point (1,6) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=1] and *[Tex \Large y_{2}=6]




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{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(6--6)/(1--3)}}} Plug in {{{y[2]=6}}},{{{y[1]=-6}}},{{{x[2]=1}}},{{{x[1]=-3}}}



{{{m=12/4}}} Subtract the terms in the numerator {{{6--6}}} to get {{{12}}}.  Subtract the terms in the denominator {{{1--3}}} to get {{{4}}}

  

{{{m=3}}} Reduce


  

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Answer:


So the slope of the line through the points (-3,-6) and (1,6) is {{{m=3}}}