<PRE><B>Question 142299</B>
square root of 3x^4y^3 divided the sqaure root of 9xy^5 
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= sqrt[3x^4y^3/9xy^5]

Multiply numerator and denominator by xy so the denominator becomes
a perfect square:

= sqrt[3x^5y^4/9x^2y^6]

Simplify the denominator:

= sqrt[3x^5y^4] / 3xy^3

Simplify the numerator:

= [x^2y^2/3xy^3] sqrt(3x)

Reduce the fraction:

= [x/3y]*sqrt(3x)
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Cheers,
Stan H.</PRE>