Question 142279
Do you mean like this??? {{{(sqrt(3x^3)/sqrt(4y^2)) * (sqrt(9x^2)/sqrt(2y^4))}}} 


I would put it together into one square root:{{{ sqrt(((3x^3)/(4y^2)) * ((9x^2)/(2y^4)) ) }}} 


Simplify:  {{{sqrt((27x^5)/(8y^6)) }}}


Put all the perfect square factors in the first square root, and leftover factors in the second square root: {{{ sqrt(((9x^4)/(4y^6)) * ((3x)/(2)) ) }}} 

{{{  ((3x^2)/(2y^3)) * sqrt((3x)/(2)) ) }}} 


Rationalize the denominator of the second fraction by multiplying inside the radical by {{{2/2}}}.

{{{  ((3x^2)/(2y^3)) * sqrt(((3x)/(2))*(2/2) )   }}} 


Simplify: 
{{{  ((3x^2)/(2y^3)) * sqrt((6x)/4 ) }}} 
{{{  ((3x^2)/(2y^3)) * ((sqrt(6x))/2)  }}} 
{{{  ((3x^2)/(4y^3)) * (sqrt(6x))  }}} 


For more help on square roots, please see my own user-friendly explanation by clicking on my tutor name "rapaljer" anywhere in algebra.com.  Click on the second link on my homepage, which is "Basic, Intermediate, and College Algebra: One Step at a Time."  You may need to see Basic Algebra in Chapter 5, or click on Intermediate Algebra and choose Chapter 3.  Explanation varies in level of difficulty between these two.  If you want College Algebra, go to the MATH IN LIVING COLOR pages, and Choose College Algebra, Chapter 1.  


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