Question 142212


{{{r/2-8=-4}}} Start with the given equation




{{{(2)(r/cross(2)-8)=(2)(-4)}}} Multiply both sides by the LCM of 2. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{r-16=-8}}} Distribute and multiply the LCM to each side




{{{r=-8+16}}}Add 16 to both sides



{{{r=8}}} Combine like terms on the right side


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Answer:

So our answer is {{{r=8}}}