Question 21441
{{{3/(x^2-2x+1)}}}+{{{3/(x^2-4x+3)}}}
{{{3/(x-1)(x-1)}}}+{{{3/(x-3)(x-1)}}}
{{{3/(x-1)(x-1)(x-3)}}}+{{{3/(x-3)(x-1)(x-1)}}}
since the denominators are now the same, you can add them up
={{{6/(x-1)(x-1)(x-3)}}}


simplified, it would be
={{{6/(x-3)(x^2-2x+1)}}}
={{{6/(x^3-2x^2+x-3x^2+6x-3)}}}
={{{6/(x^3-5x^2+7x-3)}}}