<PRE><B>Question 142053</B>
The point (-1/2,sqrt3/2) on the unit circle is rotated 60 degrees clockwise. Determine the coordinates of the new point.
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The point is in the 2nd Quadrant.
The reference angle is inverse sin(1/2) and inverse cos(sqrt(3)/2) is 
30 degrees.
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The angle of the given point in the 2nd quadrant  is 180-30 = 150 degrees
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You rotate 60 degrees clockwise and end up at 90 degrees
where the coordinates are (0,1).
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Cheers,
Stan H.</PRE>