Question 141993
{{{5-(2)/(x-6) = (10-2x)/(x-6)}}}
Notice that if you multiply both sides by <font color="blue">x-6</font>,
5(x-6)-2=10-2x
(5x-30)-2=10-2x
5x-30-2=10-2x
5x-32=10-2x
5x+2x-32=10-2x+2x
7x-32=10+0=10
7x-32+32=10+32
7x+0=7x=42
x=6

Check:
{{{5-2/(6-6) = (10-2x)/(6-6)}}}
{{{5-2/0=(10-2x)/0}}}

We all know that division by ZERO is undefined therefore there is NO SOLUTION

Power up,
HyperBrain!