Question 21447
let the 2 numbers be x and y .we have 
xy=75.......I..........
x/y=3.................II.
x-y=10....................III
.actually 2 relations should do to solve the problem
from II,we have....x/y=3
x=3y.......
substituting in I we get 
xy=3y*y=75
y*y=75/3=25
y=5
so x =3y=3*5=15
so 5 and 15 are the 2 numbers .incidentally this satoisfies the third relation of x-y =15-5=10...so no problem this is the answer...otherwise we would have to say NO ANSWER!!!!