Question 141641
This is just asking you to substitute each respective value into the original equation:

{{{f(x)=3x^2-3x}}}
{{{f(0)=3(0)^2-3(0)=0-0=0}}}
{{{f(-1)=3(-1)^2-3(-1)=3+3=6}}}
{{{f(2)=3(2)^2-3(2)=12-6=6}}}