Question 141449
To find the intercepts, we will first set x=0 and then y=0:

{{{y=-6}}} <--- y-intercept
{{{0=2x^2+4x-6}}}
Now we need to solve the second equation:
Factor:
{{{0=(2x-2)(x+3)}}}
This can only be when x=1 or x=-3. <---x-intercepts


The vertex is where the function is at a minimum. I will give you a little calculus after this, but it suffices to say that the vertex is x=-b/(2a)  when given a polynomial of form ax^2+bx+c. So the vertex per that formula is: x=-4/4=-1
which gives a y value of 2-4-6=-8. The ordered pair, then, is (-1,-8).

Calculus:
We find the critical points: 
f'(x)=4x+4
0=4x+4
-->x=-1
We then proceed as before, finding that the ordered pair is (-1,-8).


Graph:
{{{graph( 300, 200, -5, 5, -10, 10, 2x^2+4x-6 )}}}