Question 141301
80*40/2=(80-x)(40-x)
3200/2=3200-120x+x^2
1600=3200-120x+x^2
x^2-120x+3200-1600=0
x^2-120x+1600=0
using the quadratic equation:{{{x=(-b+-sqrt(b^2-4*a*c))/(2*a)}}} we get:
x=(120+-sqrt[-120^2-4*1*1600])/2*1 
x=(120+-sqrt14,400-6,400])/2
x=(120+-sqrt8,000)/2
x=(120+-89.44)/2
x=(120-89.44)/2
x=30.56/2
x=15.28' is the width of the mowed area that contains one half the total area.