Question 141330
I need help solving Radical Equations, because i dont really understand it yet.
one of my questions is 

          {{{sqrt(5x)-2= 3}}} 
<pre><font size = 4 color = "indigo"><b>
Isolate the radical on the left by adding 2 to both sides

          {{{sqrt(5x)-2+2= 3+2}}}

          {{{sqrt(5x)= 5}}}

Now square both sides of the equation:

          {{{(sqrt(5x))^2= (5)^2}}}

When you square a square root, you take away the radical:

          {{{5x= 25}}}

Divide both sides by 5:

          {{{(5x)/5=25/5}}}

          {{{x = 5}}}

But you MUST check square root equations because sometimes
an answer you get won't check in the original equation:

          {{{sqrt(5x)-2= 3}}}

Substitute {{{5}}} for {{{x}}}

          {{{sqrt(5(5))-2= 3}}}

          {{{sqrt(25)-2= 3}}}

          {{{5-2= 3}}}

          {{{3= 3}}}

So the solution {{{x=5}}} checks.

Edwin</pre>