<PRE><B>Question 141248</B>
If the circle with centre(0,m) has equation x^2+y^2+6y+5=0, what is the value of m?
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x^2+y^2+6y+5=0
Complete the square on the y-terms:

x^2 + y^2+6y+9 = -5+9

(x-0)^2 + (y+3)^2 = 4

This circle has center at (0,-3) and a radius of 2
So m = -3
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Cheers,
Stan H.

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