Question 141205
Given: {{{ x^2 – 3x = -6x – 1}}}
{{{ x^2 +3x +1 = 0}}}

Now you use the quadratic equation with a=1, b=3 c =1
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 


Given: {{{ x^2 – 10x – 1 = -10}}}
{{{ x^2 – 10x + 9 = 0}}}

Now you use the quadratic equation with a=1, b=-10 c =9
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}