Question 141198
 How many solutions are possible in: 
{{{j(d)= -47d^56 = 16d^47 - 12d^5 + 13}}} 
<pre><font size = 4 color = "indigo"><b>
You have two equal signs there.  Did you mistype that?

I'll assume you meant to type a + sign and forgot to press the shift key.

So I'll assume it's:
</pre></font></b>
 How many solutions are possible in: 
{{{j(d)= -47d^56 + 16d^47 - 12d^5 + 13}}}
<pre><font size = 4 color = "indigo"><b>
Also, your teacher or book author misstated the sentence.

Only equations and inequalities can be said to have solutions.

Functions cannot be said to have solutions.  They have zeros.

So I'll assume the question was:
</pre></b></font>
 How many zeros (or roots) are possible in: 
{{{j(d)= -47d^56 + 16d^47 - 12d^5 + 13}}}
<pre><font size = 4 color = "indigo"><b>
The rule is:

It is possible for an n-degree polynomial to have as many as 
n zeros or roots.

Therefore since the polynomial function:

{{{j(d)= -47d^56 + 16d^47 - 12d^5 + 13}}}

has degree 56, the largest exponent of a variable, then it is 
possible for it to have as many as 56 zeros or roots.

If you must use the word "solution", you can say: 

It is possible for the polynomial equation

{{{-47d^56 + 16d^47 - 12d^5 + 13 = 0}}}

to have as many as 56 solutions.

So the correct choice would be (b).

Edwin</pre>