Question 141148
LET X, X+2 & X+4 BE THE 3 CONSECUTIVE ENEN INTEGERS.
3(X+4)=2(X+X+2)
3X+12=2(2X+2)
3X+12=4X+4
3X-4X=4-12
-X=-8
X=8 FOR THE SMALLEST INTEGER.
8+2=10 FOR THE MIDDLE INTEGER.
8+4=12 FOR THE LARGEST INTEGER.
PROOF:
3*12=2(8+10)
36=2*2*18
36=36