Question 21364
1)3(x-6)=-2x-3
Distribute the 3 on the left of the =;
3x-18=-2x-3
add 2x to both sides;
3x-18+2x=-2x-3+2x
5x-18=-3
add 18 to both sides;
5x-18+18=-3+18
5x=15
divide both sides by 5;
x=3
2)(2x-5)=7
ad 5 to both sides;
2x-5+5=7+5
2x=12
divide both sides by 2;
x=6

Graph:
For these you choose an integer for x and then solve for y, you need to choose 3 integers so you can get a line on the graph.
y=-2x+1
1)x=1
y=-2(1)+1
y=-2+1
y=-1
2)x=0
y=-2(0)+1
y=1
3)x=2
y=-2(2)+1
y=-4+1
y=-3
so your points are: (1,-1) (0,1) (2,-3)
Can you do the next by yourself?
3x-2y=8

Inequality:
solving these by treating the inequality sign just as an = sign, 
16-3x<5x
add 3x to both sides;
16<5x+3x
16<8x
Divide both sides by 8;
2<x
When you are multiplying or dividing negative number you need to switch the inequality sign;
72< -12x
{{{72/-12}}}>{{{-12x/-12}}}
-6>x
Hope you understand
=)