Question 141026
2x^2 – x – 1 = 0
2x^2-2x+x-1 = 0
2x(x-1)+(x-1) = 0
(x-1)(2x+1) = 0
x-1 = 0 or 2x+1 = 0
x = 1 or x = -1/2
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Checking:
x=1:
2*1^2 - 1 -1 = 0
2-1-1 = 0
0=0
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x=-1/2
2(-1/2)^2-(-1/2)-1 = 0
2(1/4) + 1/2 - 1 = 0
1/2 + 1/2 - 1 = 0
1 - 1 = 0
 0 = 0
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Cheers,
Stan H.