Question 140969
Solve, using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{6x^2+12x = -5}}} Add 5 to both sides of the equation.
{{{6x^2+12x+5 = 0}}} Apply the formula; here: a = 6, b = 12, and c = 5.
{{{x = (-12+-sqrt(12^2-4(6)(5)))/2(6)}}} Simplify the right side.
{{{x = (-12+-sqrt(144-120))/12}}}
{{{x = (-12+-sqrt(24))/12}}}
{{{x = -1+(2*sqrt(6))/12}}} or {{{x = -1-(2*sqrt(6))/12}}}
{{{x = -1+(sqrt(6))/6}}} or {{{x = -1-(sqrt(6))/6}}} Final answer!