Question 140933
2x^2-3x+1=0 
{{{x=(-b+-sqrt(b^2-4*a*c))/(2*a)}}} 
x=(3+-sqrt[-3^2-4*2*1])/2*2
x=(3+-sqrt[9-8])/4
x=(3+-sqrt1)/4
x=(3+-1)/4
x=(3+1)/4
x=4/4
x=1 answer.
x=(3-1)/4
x=2/4
x=1/2 answer.