Question 140923
6x^2+3x-18=0,using quadratic formula
----------------------
Formula:
x = [-b +- sqrt(b^2-4ac)]/(2a)
-------------------
Your problem:
x = [-3 +- sqrt(9-4*6*-18)]/12
x = [-3 +- sqrt(441)]/12
x = [-3 +- 21]/12
x = (-3+21)/12 or x = (-3-21)/12
x =(3/2) or x = -2
========================
Cheers,
Stan H.