Question 140923
6x^2+3x-18=0
Following is the quadratic formula:
{{{x=(-b+-sqrt(b^2-4*a*c))/(2*a)}}}
x=(-3+-sqrt[3^2-4*6*-18])/2*6
x=(9+-sqrt[9+432])/12
x=(9+-sqrt441)/12
x=(9+-21)/12
x=(3+21)/12
x=24/12
x=2 answer.
x=(3-21)/12
x=-18/12
x=-1.5 answer.