Question 140794
Let n=first
Then n+2=second
and n+4=third

n+n+2+n+4=33 simplify

3n+6=33  subtract 6 from each side

3n+6-6=33-6

3n=27  divide each side by 3
n=9------------------------------------first integer
n+2=9+2=11----------------------------second integer
n+4=9+4=13-------------------------------third integer

CK

9+11+13=33
33=33


Hope this helps----ptaylor