Question 140771
for constant acceleration __ distance equals one half times the acceleration times the square of the time __ d=.5at^2


2d=at^2 __ 2d/a=t^2 __ sqrt(2d/a)=t


60mph=60mph(5280ft/mi)/(3600sec/hr)=88ft/sec
__ a=60mph/4sec=88ft/sec/4sec=22ft/sec^2


t=sqrt(2*1320ft/22ft/sec^2)=sqrt(120sec^2)=slightly under 11sec