Question 140692
X/X+2+ 3/X-2=7/X
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Multiply thru by the least common multiple which is x(x+2)(x-2) to get:

x^2(x-2) + 3x(x+2) = 7(x+2)(x-2)

x^3 - 2x^2 + 3x^2 + 6x = 7x^2 - 28

x^3 -6x^2 + 6x + 28 = 0
Graphing this I find a zero at x = -1.489362....
The other two zeroes are complex numbers.
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Cheers,
Stan H.