Question 140488
Calculation of the test statistic requires three components: 
1. The average of both sample (observed averages)
Statistically, we represent these as 
Ans: u1 and u2
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2. The standard deviation (SD) of both averages
Statistically, we represent these as 
s1 and s2
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3. The number of observations in both populations, represented as
n1 and n2
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From hospital records, we obtain the following values for these components: 
men women
Average age 29.87 31.67
SD 8.45 8.10
n 15 15
With these pieces of information, we calculate the following statistic, t: 
t(29.87-31.67) = (-1.8 - 0)/[8.45^2/15 + 8.10^2/15] = -1.8/3.0222 = -0.5956
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Use this value to determine p-value
p-value = p(-0.5956 < z < 10) = 0.7243...
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Having calculated the t-statistic, compare the t-value with a standard table of t-values to determine whether the t-statistic reaches the threshold of statistical significance. 
Critical value of one-tail t-test with df = 29 and alpha=5%: t=-1.645
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With a t-score -1.80 not significant, the p-value is 0.7218, a score that forms our basis to reject the null hypothesis and conclude that the age data for both male and female who purchase tickets are not 34. 
Is this a statement or a question?
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Cheers,
Stan H.