Question 21181
Let train B be represent by x and let train A be reprsented by 10+x
3(10+x+x)=150
30+3x+3x=150
6x=150-30
6x=120
{{{6x/6=120/6}}}
x=20
20+10=30. hence tarin A is traveling at 30mph and train B is traveling at 20mph