Question 140313
{{{(x-2)^2+(y+1)^2=12}}} Start with the given equation



{{{(y+1)^2=12-(x-2)^2}}} Subtract {{{(x-2)^2}}} from both sides



{{{y+1=0+-sqrt(12-(x-2)^2)}}} Take the square root of both sides



{{{y=0+-sqrt(12-(x-2)^2)-1}}} Subtract 1 from both sides



So we have the two equations 


{{{y=sqrt(12-(x-2)^2)-1}}} and {{{y=-sqrt(12-(x-2)^2)-1}}}




So when we graph the two equations we get


{{{ graph( 500, 500, -10, 10, -10, 10,sqrt(12-(x-2)^2)-1,-sqrt(12-(x-2)^2)-1   ) }}} Graph of {{{y=sqrt(12-(x-2)^2)-1}}} (red) and {{{y=-sqrt(12-(x-2)^2)-1}}} (green)