Question 140312
{{{(x+5)^2+(y-1)^2=16}}} Start with the given equation



{{{(y-1)^2=16-(x+5)^2}}} Subtract {{{(x+5)^2}}} from both sides



{{{y-1=0+-sqrt(16-(x+5)^2)}}} Take the square root of both sides



{{{y=0+-sqrt(16-(x+5)^2)+1}}} Add 1 to both sides



So we have the two equations 


{{{y=sqrt(16-(x+5)^2)+1}}} and {{{y=-sqrt(16-(x+5)^2)+1}}}




So when we graph the two equations we get


{{{ graph( 500, 500, -10, 10, -10, 10,sqrt(16-(x+5)^2)+1,-sqrt(16-(x+5)^2)+1   ) }}} Graph of {{{y=sqrt(16-(x+5)^2)+1}}} (red) and {{{y=-sqrt(16-(x+5)^2)+1}}} (green)