Question 140143
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r

Let t=amount of time required for Elizabeth to make the trip to Thomas' house

Now we know that t=d/r=71/57; t=1.25 hrs or 1 hr 15min

So 4:27 p.m. minus 1hr 15min=3:12 p.m.

Hope this helps---ptaylor