Question 140001
{{{(4m^4n^3p^3)/(3m^2n^2p^4)}}} Start with the given expression.



{{{m^(4-2)n^(3-2)p^(3-4)}}} Remember when you divide monomials, you subtract their corresponding exponents. For instance {{{x^2/x^3=x^(2-3)=x^-1}}}



{{{(4/3)(m^2n^1p^-1)}}} Simplify.  Remember to reduce the coefficients (which are numbers in front of the variables) to get {{{4/3=4/3}}}.



{{{(4/3)(m^2n/p)}}} Flip the expression with a negative exponent.



{{{(4m^2n)/(3p)}}} Simplify




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Answer:


So {{{(4m^4n^3p^3)/(3m^2n^2p^4)}}} simplifies to {{{(4m^2n)/(3p)}}}.


In other words, {{{(4m^4n^3p^3)/(3m^2n^2p^4)=(4m^2n)/(3p)}}} where {{{m<>0}}} and {{{n<>0}}}