Question 139850
Find the values of the positive numbers a and b,
:
 given that a is 8 times the size of b
a = 8b
:
and the reciprocal of ab is 1 less than 3.
{{{1/(ab)}}} + 1 = 3
:{{{1/(ab)}}} = 2; subtract 1 from both sides
2ab = 1
:
2(8b*b) = 1; substitute 8b for a
16b^2 = 1
b^2 = {{{1/16}}}
b = {{{sqrt(1/16)}}}
b = 1/4
then
a = 8*{{{1/4}}}
a = 2
:
:
Check solution in the statement:"a is 8 times the size of b"
2 = 8 * (1/4)