Question 139841
(2x^2–12x+18)/(2x^2-18) I presume that is the problem properly stated???
2(x^2-6x+9)/2(x^2-9) now cancel out the 2 terms
(x^2-6x+9)/(x^2-9)
(x-3)(x-3)/(x+3)(x-3) now cancel out the (x-3) terms
(x-3)/(x+3) answer.
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(x^2–9x+20)/(3x-15)÷(x^2–16)/(9x+36) I presume that is the problem properly stated????
factor all elements, invert the second fraction & divide them.
(x-4)(x-5)/3(x-5)*[9(x+4)/(x-4)(x+4)] now cancel out the (x-5), the (x+4), the (x-4) terms & divide the 9 by 3.
3 is the answer.