Question 21113
f(x)= (x+1)/(x^2-5x+6)
f(x)= (x+1)/(x^2-3x-2x+6)
f(x)= (x+1)/(x-3)(x-2)

f(x-1)= ((x-1)+1)/{((x-1)-3)((x-1)-2)}
f(x-1)= x/{(x-4)(x-3)}
f(x-1)= {{{x/(x^2-7x+12)}}}
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