Question 139516
3/x+3/y  divided by 3/x-3/y

(3x+3y)/xy / (3y-3x)/xy

Concel the xy denominators:

= [3(x+y)]/[3(y-x)]

Cancel the 3 factor in numerator and denominator.

= (x+y)/(y-x)

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Cheers,
Stan H.