Question 139354
The width: {{{W}}}
The length: {{{L = 2W + 2}}}  (two meters more than twice the width)
The perimeter: {{{P=2(L+W)}}}


{{{2(L+W)=34}}}, but since  {{{L = 2W + 2}}}, {{{2((2W+2)+W)=34}}}.


Solve for W and you have the width from which you can easily calculate the length.