Question 139225
First, put it into standard form:  {{{ax^2+bx+c=0}}}


{{{-1+3x^2=2x}}}
{{{3x^2-2x-1=0}}}


Now you can see that {{{a=3}}}, {{{b=-2}}}, and {{{c=-1}}}.


Substitute those values for a, b, and c into {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} and do the arithmetic.  You will find that this one is very tidy and well-behaved with a nice neat perfect square under the radical.  That is to say, nothing like real life.